Coin Mech setup Help

[xscdx]

Hi,

My first ever post here and I am sorry to say its a help post.  I have had my cab for some years now, its a custom built machine.

I have decided to try and install a coin mech, I have purchased a door with a sentinel coin mech and have got so far setting it up.

Using the supplied mech harness I have attached the +12v to the PSU's Yellow 12v and the Ov to the PSU's ground. The mech accepts the 20p I throw at it so phase one complete.

I have attached pin 1 common a (ground) to the ground of my i-pac and the p1 Accept to the Coin 1 of the i-Pac.  This is where I am stumpted, when slotting in a coin nothing is registering in notepad, I would expect to see a 5 appear.  I have attaced a 5v zener diode from the psu ground to the coin 1 so there no +12v going to the i-pac.

Is anyone able to assist or suggest where I have gone wrong? hopefully my drawing will make some sense?

Many thanks in advance.

Darren

[DaOld Man]

I know nothing about the coin mech, but you can try lifting one of the wires going to the ipac, touch it to the ground, to see if the ipac registers the key stroke. If it does, then you know it is in the coin mech and not the ipac.
Im pretty sure the ipac needs to see a ground at the input (but could be wrong, ive never wired one).
Could the coin mech be outputting a positive instead of the ground?
If you have a volt meter, test the leads coming out of the coin mech and see if you see voltage when you insert a coin.

[DaOld Man]

Also, if the coin mech puts the ground to the ipac when it sees a coin, if you need the zener, you will need to attach the zener between the ipac input and the +12 volts going to the PSU. The banded end goes to the +12.
Also, you will need a resistor between the zener and the mech, on the ipac side.
It will most likely fry the zener without the resistor unless the coin mech has some sort of current limit.

BTW, welcome to the board!

[xscdx]

Thanks for your comments chaps, I now have it working ,  after a re-think and more reading etc here is what I had to do:

1) connect the PSU +12V (Yellow) to the 12v input on the mech
2) connect the PSU GND (Black) to the Ov input on the Mech
3) connect pin 1 of the Sentinel (Common a) to the i-PAC Ground
4) connect Coin Accept in my case Pin 5 for the 20p's to the Coin 1 on i-PAC
5) IMPORTANT PART, connect the 5.1v Zenner Diode between the Coin Accept and Common a, ensuring the gate is against the Coin cable NOT the Ground. (your i-PAC will blow if not corrected right )

I learnt this at the expense of my i-PAC so had to order another, mind you I was not that fussed as I wanted the i-PAC 2, my original i-PAC is some 7/8 years old now.

So, now when I slot in a 20p a pulse is sent to the i-PAC and 5 is registered result, now to fit the coin door and mech properly.

[lilshawn]

you shouldn't need a diode on there, and you need to tie the grounds together (pc + ipac) the coin output and power is correct.

the mech coin lines are a switch to ground. (when you insert a coin it connects)

the "com a" wire just enables and disables coin acceptance. i believe it needs to be tied to v+ to accept...left floating or grounded to disable the coins.

[Dawgz Rule]

 

I have to agree with lilshawn.  I ran a ground from the PC to a terminal board and all my switches, iPac, etc run to the same ground.  From there I just ran the coin 1 from the iPac to the coin mech and all worked well. 

[xscdx]

Are you saying there is no need for the for Step 2 of my process?  I am a little worried about messing around with the wiring of it now I have it working, unfortunately I am no Electronics expert.

I also read on Ultimarc and here: http://forum.arcadecontrols.com/index.php/topic,83990.0.html
this forum that the Zener Diode should be connected to limit the voltage going to the i-PAC.

Are you running a Sentinel also? would you be able to upload some pics of your wiring for me?  Many thanks.

 

[lilshawn]

the coin line is a switch to ground. there is no pulse of power.

it's no different than connecting the coin line wire coming from the ipac to ground.

the only reason you would need a diode would be if you where trying to drive 2 disimilar systems with the same line (drive a coin line and a coin counter for instance) the power from the coin counter would feed back into the line causing nothing to happen.

if you just power the coin mech (12 volta and ground) does it accept coins properly?