Could you post a pic of your marquee replaced with a piece of opaque white plexi and specify the distance from the marquee so that we can get a realistic idea of the quality of the light distribution?
I don't have a piece of white plexi available to do this. Even if I did, photographing what would essentially be a diffused light is so difficult that the result would probably not be particularly meaningful. Likewise, the pictures above really don't do justice to the end result.
Your lit marquee in the pic of your first post makes the sides look dim. Is this the marquee artwork, or the light distribution?
I'm not sure if you noticed, but just in case, you can get a little larger image by clicking it. If you look at the upper left section of my marquee, you'll see where the shadow from the interior marquee frame has a gap and where the light is being cast into that far corner. Even with a fairly bright light on in the room, I can still see that shadow of the frame, so it is well illuminated.
What you are seeing is a lot of the artwork and a little of the light distribution. The background at the edges is a shade lighter than that which is behind the O and C in the middle. The Red on the ends is also a much darker shade than the rest of the colors in the text. The skewed rectangular frame is a gradient, which gets darker at the upper right and lower left of the frame.
What is the distance from light to marquee in that pic? It appears to be mounted on the back panel of the cabinet?
No, it's mounted directly to the sides of some downward facing amplified speakers. The lights are about 6" away from the back face of the marquee.
There are 16 LEDs on each board, spaced about .65" apart on centers. The cone for each LED is about 110 degrees. With these pieces of data, you should be able to calculate relative light density and distribution
A properly rated potentiometer should work for a dimmer as well.
What would the rating of that be? Or, what are the ratings of the light strip so that one could calculate the proper rating?
Unless you use two units together in one cabinet, I doubt that a potentiometer will be necessary. Each unit draws about 370ma, so 5 watts should be sufficient. But, whatever one decides to do there is ultimately up to them. I take no responsibility if the potentiometer one decides to use melts or catches fire.
RandyT