Ok, Ive got an Overhead (brand) garage door opener.
I have made a combination lock circuit which I would like to use to open the door from the outside of the garage.
The circuit I built will basically "short out" the two wires going from the door opener unit to the (inside) wall mounted button, if the proper combination is entered from a 12 digit keypad.
I would like to use an opto isolator to short out these two wires.
But it wont work.
The inside wall button has a button to lower/raise the door, a button to turn on a lamp that is mounted on the opener unit, and a switch that can disable the button and the radio remote (for going on vacation or whatever).
The wall button only has two wires going to it.
I can short out the two wires and the door will raise or lower.
But if I use an opto isolator to short out the two wires, it wont raise the door, but it does turn on and off the lamp.
My first guess was that it is probably an AC signal. AC coming back to the unit will raise the door, but a DC will turn on the lamp. I theorized the lamp button probably placed a diode across the two wires, same effect the opto isolator would have. But I tried a solid state relay, which can switch AC, and it still just turns on the lamp.
So what is going on? Im afraid I will break the wall button if I try to take it apart to see whats inside.
And how is does the "vacation" switch work? With this switch turned to "lock", shorting out the two wires does nothing.
I have searched the internet trying to find out what is going on with this probably very simple circuit, but I cant find anything.
I guess I can use a relay for my project, but I really wanted to stay away from relays, due to physical size and power requirements.
Can anyone give me some insight on this?
And BTW, if anyone is interested in my combination lock circuit, I will be glad to post schematics and pics, although it is way off topic for this forum.