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Author Topic: WinIPAC default layout?  (Read 819 times)

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waname

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WinIPAC default layout?
« on: December 22, 2004, 08:20:13 am »
Sorry- I should have tried this out before Andy went on vacation!

I just fired up the WinIPAC utility and all my buttons are responding correctly.

The thing I don't understand is that from the web site I thought that the default layout of the IPAC has lots of useful shifted functions.  In fact, I'm sure that they work.

But if I fire up WinIPAC and choose to look at the shifted key values, P1 B1 is "z" and most of the other buttons aren't mapped at all.  Does anybody know why this is?

It's probably no big deal- I just have to enter the correct mappings.  But it shouldn't be this way, and that always makes unfamiliar users hesitant to stray from what they know.

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