I have it figured like so:
1" knob with 1" wheel = 1:1 rotation
1" knob with 10" wheel = 10 encoder wheel rotations per 1 knob rotation.
Craig, you are off base here, or at least are presenting your thoughts in a very misleading way. 1 revolution of the knob always equals one revolution of the encoder wheel. The sizes, more likely than not, have more to do with the ability of an individual (or laser cutter) to create the number of "teeth" in the selected medium and do it accurately. If the minimum size aperture you can create is .100" , then it stands to reason that a 72 aperture encoder will need to have a circumference of (72 x 2) x .1 or 14.4". If I still remember my geometry, that comes out to a diameter of a little over 4 1/2".
However, if you use the same
pitch on a larger diameter, you will obviously be increasing the resolution of the wheel, and sending more data per revolution. But the ratio will always be 1:1.
The problems come when you use very fast movements with slow mouse circuitry, or exceed the original aperture count (resolution) of the mouse encoder. If you are looking for mice to hack, look for ones that claim to be "high-resolution", and stick with newer ones rather than some very old junker from the dark ages.
And while projects like this one can be fun, unless you have a lot of time on your hands and very little money, you may find that end result is a little disappointing based on the effort required to do it. Those who place value on their time will likely want to look for a different solution.
FWIW,
RandyT
I see Julian also chimed in. Too slow again
