That won't work right with a BJT since you need to source current into the base of the transistor and get it to flow out the collector (for an NPN). This means you need a voltage ABOVE the input rail to have the load on the emitter with an NPN.
You can, however, use a PNP for this. When the signal on the base is connected to ground, current flows from the emitter (which is connected to the power rail), through the base, and into the signal source. This causes a bunch of current to flow out the collector and into the load.
If you can't change the transistor, put a pull-up resistor on each output and use a 74xx04 to invert the signal and feed that into the strip as-is.