Not to derail things, but I don't think I know enough terminology, or what's connected to what, and I'd really like to. As far as I was aware, the heater/filament voltage heated the cathodes. So what does the R,G & B voltage do, what does it energise, specifically? It's at -116V relative to common ground, correct? And the signal is laid on top of that? If the other end of the RGB voltages is common ground, what do those pink numbers mean? They're not all -116V, so do the different guns require different bias/gain voltages? (Which last would make sense, if the different phosphors aren't perfect, even emitters; and there's no reason they should be).
Here's my (ever evolving) understanding, and forgive me if much of what I say is obvious to you.
The -116V indicates the voltage between the cathode and G1 that is associated with a video signal level of 0. I'm still not conceptually fluent enough with circuits and electricity theory to grok how the concept of ground plays into this, but the way I understand it is that G1 has a negative voltage with respect to the cathode (does this mean that the cathode has a positive voltage with respect to G1? Or do we need ground here to make sense of it all?). There are three cathodes, one for each of the three channels. I believe, but am not 100% certain, that there is only one G1 common to all three cathodes (and one G2).
Now when G1 is negative with respect to, say, the green cathode, this means that electrons originating from the cathode, which would otherwise be accelerated by the positive voltage at G2, are repelled. When, say a video level of 100% for this channel is sent to the tube (i.e. RGB [0,255,0]), this causes the magnitude of the voltage difference between the green cathode and G1 to decrease. And now, because there's less repulsion between G1 and the green cathode, full beam current is achieved (relative to the brightness setting, which controls the bias at G2 (relative to G1?) ).
Now I believe that those pink numbers indicate the G1-cathode voltages required for appropriately balanced peak luminances (probably for a D65 chromaticity - see the intro to my WinDAS white point balance guide for some basics in color theory)
https://hardforum.com/threads/windas-white-point-balance-guide-for-sony-trinitron-crts.1830788/Assuming this is correct, the reason that the voltages aren't identical is due to the following reasons:
The relative balance of the luminance of the red, green, and blue phosphors (SMTPE-C phosphors, which correspond to the primaries associated with the BT.601, or SD, standard, and which are very close to the primaries for Rec.709 HD standard/sRGB primaries) needed to achieve a white point of D65 is not 1:1:1. It's more like 22% red, 71% green, 7% blue.
Secondly, the spectral energy of each of these phosphors does not contribute equally to luminance. You need to apply the luminosity function, which is a spectrally weighted sum, to calculate luminance. For example, as the spectral power distribution of the green phosphor overlaps the luminosity function more than that of the blue phosphor, this means that you need more radiant flux from the blue phosphor than from green to achieve the same luminance (you can think of luminance as perceptually weighted radiance).
Finally, the radiant efficiency of each of the three phosphors (how much radiant flux is produced per unit beam current) is not necessarily equal.
When you combine these three factors, you presumably end up with the voltages listed in the schematic, and this also presumably does not take into account cathode aging.
Interestingly, in the service manual for the Sony CPD-G520, which is a 21 inch trinitron, the pink annotations are different.
(Incidentally, I have a PC monitor that's having problems with bias voltage (Should be lower for a bright screen, I think. I watch it rise to -55V as the screen fades within about a 1 second). What should I check? Is there a name for that line?)
What do you mean by "that line"? Based on my understanding (see above in this post), the magnitude of the bias voltage should rise as the video signal goes to 0. Are you suggesting that the bias voltage should rise to something like -50V with a video signal of 0 (instead of -55V)? What symptoms are your monitor displaying? If it's too bright at video signal of 0, then you probably need to recalibrate the cutoff voltage at G2 (i.e. reduce it slightly).
Happy to help, of course. Most of that post was warnings and guesswork though! And by kit I simply meant the portable suitcase stuff local TV repairmen would use. Heathkits used to come as just that, I believe, you built them yourself from the parts. As opposed to the tailored facilities available at the factory.
Interesting! Just looked it up, looked like a good way to learn and save money
Any chance you're in Australia and want to sell me one of those FW-900's?
Ah, sorry. Toronto, Canada. Plus I may only have 2 working FW900s now, depending on whether or not I destroyed one of my units when I first tried using the Sencore on it
Set up a google alert though, you never know what might appear on your local craigslist or ebay.
Also, there's this thread, which has been going strong for over 11 years:
https://hardforum.com/threads/24-widescreen-crt-fw900-from-ebay-arrived-comments.952788/p.s. this verification step where I have to input the letters in order to post is annoying and frustrating. Will it stop once I've become a more regular poster?