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Can't Bullseye Womprats In My T16!!

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Beley:


--- Quote from: waveryder on January 22, 2008, 03:00:38 am ---......I have done a little more research and have found that on amp building forums people are using 4K7 linear pots to replace 5K's as the tolerance makes them essentially the same thing. Can anyone enlighten me on that? ........
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A 5kohm pot with a 10% tolerance (most are 10-20%) could be anywhere from  4.5k to a 5.5k
A 4.7kohm pot with a 10% tolerance could be anywhere from a 4.23k to a 5.17k

as you can see its quite possable to buy a 4.7k and a 5k and have the 4.7k pot have a higher resistance then the "bigger" 5k pot

the actual difference between a 5k and a 4.7 is only ~1%, significantly less then the tolerance

waveryder:

Surely then that ~1% can compensated for by the Dual Strikes/mame's configuration.

waveryder:

Started playing with the DS pcb today and measured the existing pot. Its a 20K, the sidewinder is restricted by a plastic stopper from turning very far so it never uses all of the pots turn. I have played around with the settings using just the estimated 4k7 pot turn and it works perfectly and Ive managed to have a quick game of starwars. Now to get on with the final build.


jukingeo:


--- Quote from: waveryder on January 24, 2008, 07:37:27 am ---Started playing with the DS pcb today and measured the existing pot. Its a 20K, the sidewinder is restricted by a plastic stopper from turning very far so it never uses all of the pots turn. I have played around with the settings using just the estimated 4k7 pot turn and it works perfectly and Ive managed to have a quick game of starwars. Now to get on with the final build.


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Which version of Star Wars is this?

SavannahLion:


--- Quote from: NickG on January 21, 2008, 03:33:42 pm ---if you really need exactly 5KΩ over exactly 270°, then you can use a 10KΩ 300° pot in parallel with a 12.5KΩ resistor.  For the 12.5KΩ you can dial a 15KΩ variable resistor down to 12.5KΩ.  This way, you can calibrate the full range of the yoke with the variable resistor.  

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I think I'm doing my math wrong. I figure 10KΩ 300° restricted to 270° amounts to a 9KΩ pot. If one wants 5KΩ out of that, I figure ~11.1K would be the resistor to use. Am I missing something?

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