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| How to power something w/ a nicad camcorder battery? |
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| Jakobud:
I figure someone on here is going to have an idea of where I should look online for information on how to do this... I have this thing that runs off of 8 AA batteries. I want to get rid of the batteries and run it off of a Sony camcoder battery. I know I will probably have to build some sort of little circuit to regulate voltage and current correctly... Anyways, if anyone has any sort of online resource for someone learning how to do things like this please show me the way :) |
| romid:
Im thinking all you need to know are the basics: a) how a voltage splitter works (two resistors in series) b) Voltage = Current * resistance c) the configuration of the batteries (series? parallel?) to see how much voltage is being supplied maybe you can search for "v=ir" in google (voltage=current*resistance) to learn some basic EE stuff |
| RandyT:
--- Quote from: Jakobud on February 26, 2003, 05:28:55 pm ---I have this thing that runs off of 8 AA batteries. I want to get rid of the batteries and run it off of a Sony camcoder battery. I know I will probably have to build some sort of little circuit to regulate voltage and current correctly... --- End quote --- I'm confused... :) 8 AA batteries = 12v Camcorder battery = not 12v ? ??? Unless you are running LEDs or something like that, your device should only use as much current as it requires. ie. most cases, there's no need to limit it. Is the camera battery 12v? RandyT |
| romid:
it's also possible that his device has (4 batteries in series) in parallel with (4 batteries in series) which would make it 6 volts. I think as long as the camcorder battery has a higher voltage then what the device requires, you can always use a voltage splitter to provide the device with the correct amount of voltage. |
| RandyT:
--- Quote from: romid on February 26, 2003, 06:43:58 pm ---it's also possible that his device has (4 batteries in series) in parallel with (4 batteries in series) which would make it 6 volts. --- End quote --- Wouldn't it make more sense to just use 4 C cells in this case :). I guess it's possible, but not very likely. So what are we powering here :) ? RandyT |
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