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Will a coin door operate ok with a jpac?

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eggedd2k:

thinking about it, surely the coin door gets it's 12v directly via the PSU - not via the jamma edge connector

wpcmame:


--- Quote from: eggedd2k on June 21, 2005, 04:28:46 am ---thinking about it, surely the coin door gets it's 12v directly via the PSU - not via the jamma edge connector

--- End quote ---
Sorry I messed it up and remebered wrong.

In my cabinet the coin mech is attached to the 12V on the jamma connector (which ofcourse comes from the PSU). Was probably easier to draw all cables from the coin mech to one place.

My problem was that the coin mech alone didn't provide enough load for the PSU to work properly. Therefore I disconnected the cabinet PSU and draw a cable from the PC PSU to the JPAC. On the JPAC there is no screw connetor for the 12V so that is why I soldered the cable directly on the JPAC.

AlanS17:

I didn't think I would have enough load on mine but apparently I did after all. Never caused me a problem.

eggedd2k:

i've just had a word with ultimarc. they said that i should check the voltage on the two coin inputs on the jamma connector. they said that it needs to be no higher than 5volts.

pcb:


--- Quote from: eggedd2k on June 21, 2005, 10:54:28 am ---i've just had a word with ultimarc. they said that i should check the voltage on the two coin inputs on the jamma connector. they said that it needs to be no higher than 5volts.

--- End quote ---

Why would the coin inputs need voltage at all!.  It's just a switch, no?
Just like a standard button. The input (coin input) is ogically held high by the gameboard, then temporarily grounded to go low and tell the board a coin was entered.  This should be the same with anything plugged into a JAMMA harness.

Am I missing somthing here?

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